Python – 可以在不明确使用名称的情况下调用自身吗？

或者更广泛的问题：如何在python中创建递归函数,并且在更改其名称时,只需要在声明中进行更改？ 最佳答案 我发现了一个简单,有效的解决方案

from functools import wraps

def recfun(f):
    @wraps(f)
    def _f(*a,**kwa): return f(_f,*a,**kwa)
    return _f

@recfun
# it's a decorator,so a separate class+method don't need to be defined
# for each function and the class does not need to be instantiated,# as with Alex Hall's answer
def fact(self,n):
    if n > 0:
        return n * self(n-1)  # doesn't need to be self(self,n-1),# as with lkraider's answer
    else:
        return 1

print(fact(10))  # works,as opposed to dursk's answer

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